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5k^2-45k+90=0
a = 5; b = -45; c = +90;
Δ = b2-4ac
Δ = -452-4·5·90
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-15}{2*5}=\frac{30}{10} =3 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+15}{2*5}=\frac{60}{10} =6 $
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